Jumat, 14 Desember 2012

Cholesterol

Introduction to Cholesterol
Cholesterol, from the Greek chole- (bile) and stereos (solid) followed by the chemical suffix -ol for an alcohol, is an organic chemical substance classified as a waxy steroid of fat. It is an essential structural component of mammalian cell membranes and is required to establish proper membrane permeability and fluidity.
In addition to its importance within cells, cholesterol also serves as a precursor for the biosynthesis of steroid hormones, bile acids, and vitamin D. Cholesterol is the principal sterol synthesized by animals; in vertebrates it is formed predominantly in the liver. Small quantities are synthesized in other cellular organisms (eukaryotes) such as plants and fungi. It is almost completely absent among prokaryotes (i.e., bacteria).
Although cholesterol is important and necessary for human health, high levels of cholesterol in the blood have been linked to damage to arteries and cardiovascular disease.
François Poulletier de la Salle first identified cholesterol in solid form in gallstones in 1769. However, it was only in 1815 that chemist Eugène Chevreul named the compound "cholesterine".

Structure of Cholesterol 
Cholesterol is also an important component of animal membranes (plant membranes have a similar, but distinct 'sterol' in their membranes). It is a lipid, because it is composed almost entirely of carbon and hydrogen, but it is different from fatty acids, fats and phospholipids in that it is arranged in a series of rings. The rings consist of 5 or 6 carbon atoms bonded together. The carbon atoms at the apices of the hexagonal and pentagonal rings have hydrogen atoms attached to them. The ring-like structures are fairly rigid, but there is also a hydrocarbon tail, which is somewhat flexible. The entire structure is somewhat reminiscent of a fancy kite with a tail.  

Structure of Cholesterol

Cholesterol is very non-polar, except for the hydroxyl group attached to the first ring. Consequently, in an animal cell membrane the polar hydroxyl group sticks into the aqueous environment (either extracellular water or intracellular water), and the rest of the cholesterol molecule, which is non-polar, is found among the non-polar fatty acid tails of the phospholipids.The image below depicts a section of a cell membrane with water outside and inside. The polar head groups of the phospholipids are represented in red, and their non-polar fatty acid tails are shown as zig-zag lines extending from the polar head group. As we we see in greater detail, cell membranes consist of a bilayer of phospholipids with other molecules inserted into the bilayer. This illustration shows five cholesterol molecules (the black structures with four conjoined rings) inserted into the lipid bilayer. Most of the cholesterol molecule in non-polar and therefore associations with the non-polar fatty acid tails of the phospholipids. However, the hydroxyl group (-OH) on cholesterol carries a negative charge and therefore associates with the polar environment of water either inside the cell or outside.
Biosynthesis
All animal cells manufacture cholesterol with relative production rates varying by cell type and organ function. About 20–25% of total daily cholesterol production occurs in the liver; other sites of higher synthesis rates include the intestines, adrenal glands, and reproductive organs. Synthesis within the body starts with one molecule of acetyl CoA and one molecule of acetoacetyl-CoA, which are hydrated to form 3-hydroxy-3-methylglutaryl CoA (HMG-CoA). This molecule is then reduced to mevalonate by the enzyme HMG-CoA reductase. This step is the regulated, rate-limiting and irreversible step in cholesterol synthesis and is the site of action for the statin drugs (HMG-CoA reductase competitive inhibitors).
Mevalonate is then converted to 3-isopentenyl pyrophosphate in three reactions that require ATP. Mevalonate is decarboxylated to isopentenyl pyrophosphate, which is a key metabolite for various biological reactions. Three molecules of isopentenyl pyrophosphate condense to form farnesyl pyrophosphate through the action of geranyl transferase. Two molecules of farnesyl pyrophosphate then condense to form squalene by the action of squalene synthase in the endoplasmic reticulum. Oxidosqualene cyclase then cyclizes squalene to form lanosterol. Finally, lanosterol is then converted to cholesterol through a 19 step complex process.
Konrad Bloch and Feodor Lynen shared the Nobel Prize in Physiology or Medicine in 1964 for their discoveries concerning the mechanism and regulation of cholesterol and fatty acid metabolism.

Regulation of Cholesterol Synthesis
Biosynthesis of cholesterol is directly regulated by the cholesterol levels present, though the homeostatic mechanisms involved are only partly understood. A higher intake from food leads to a net decrease in endogenous production, whereas lower intake from food has the opposite effect. The main regulatory mechanism is the sensing of intracellular cholesterol in the endoplasmic reticulum by the protein SREBP (sterol regulatory element-binding protein 1 and 2). In the presence of cholesterol, SREBP is bound to two other proteins: SCAP (SREBP-cleavage-activating protein) and Insig1. When cholesterol levels fall, Insig-1 dissociates from the SREBP-SCAP complex, allowing the complex to migrate to the Golgi apparatus, where SREBP is cleaved by S1P and S2P (site-1 and -2 protease), two enzymes that are activated by SCAP when cholesterol levels are low. The cleaved SREBP then migrates to the nucleus and acts as a transcription factor to bind to the sterol regulatory element (SRE), which stimulates the transcription of many genes. Among these are the low-density lipoprotein (LDL) receptor and HMG-CoA reductase. The former scavenges circulating LDL from the bloodstream, whereas HMG-CoA reductase leads to an increase of endogenous production of cholesterol. A large part of this signaling pathway was clarified by Dr. Michael S. Brown and Dr. Joseph L. Goldstein in the 1970s. In 1985, they received the Nobel Prize in Physiology or Medicine for their work. Their subsequent work shows how the SREBP pathway regulates expression of many genes that control lipid formation and metabolism and body fuel allocation.
Cholesterol synthesis can be turned off when cholesterol levels are high, as well. HMG CoA reductase contains both a cytosolic domain (responsible for its catalytic function) and a membrane domain. The membrane domain functions to sense signals for its degradation. Increasing concentrations of cholesterol (and other sterols) cause a change in this domain's oligomerization state, which makes it more susceptible to destruction by the proteosome. This enzyme's activity can also be reduced by phosphorylation by an AMP-activated protein kinase. Because this kinase is activated by AMP, which is produced when ATP is hydrolyzed, it follows that cholesterol synthesis is halted when ATP levels are low.

Cholesterol Extraction Method
  1. Homogenize 1 x 10e6 cells or ~10 mg tissue into either 200 uL chloroform-methanol (v/v 2:1) or 200 uL hexane-isopropanol (v/v 3:2).
  2. Centrifuge for 5-10 min at 14,000 rpm in a microcentrifuge.
  3. Transfer the organic phase to a clean tube and vacuum dry.  Store the material in the freezer (<20oC), desiccated and protected from air, i.e., under anaerobic conditions to minimize oxidation.
  4. Re-dissolve the vacuum-dried lipids/cholesterol into a suitable assay buffer prior to use.
 Isolation of Cholesterol from Egg Yolk
Procedure: In a 250 mL round bottom flask, combine a hard-boiled egg yolk, 1 g of K2CO3, 5 g of sand, and 10 mL of MeOH. Grind together until it is smooth – it will look like soft scrambled eggs. Add 20 mL of cyclohexane, stir thoroughly – it will look like corn meal mush – then warm to reflux. Rotovap off the solvent. While the solvent is rotovapping, prepare a chromatography column with 15 g of flash silica gel and a layer of sand on top, and have fifteen test tubes ready to take fractions. Also prepare a mixture of 30 mL of EtOAc and 170 mL of petroleum ether. To the 250 mL round bottom flask with the egg mixture, add 30 mL CH2Cl2, and stir thoroughly. Add the CH2Cl2 solution (not the egg mixture!) to the top of the column, and let the solvent go down on its own. When all the CH2Cl2 is down, rinse the inside top of the column with a little of the EtOAC/pet ether mixure. By this time, the solvent should have begun to drip out of the bottom of the column. Add more of the EtOAC/pet ether mixure to the top of the column, and apply gentle air pressure to the column as you collect 10 mL fractions. You should collect 15 fractions. Check the fractions by thin layer chromatography. Usually, the cholesterol comes in fractions 6-10. Rotovap the cholesterol fractions in a tared round bottom flask. You should be rewarded with iridescent rosettes of the product. Record the weight and the melting point.
Option #1: Cholesterol forms a specific 2:1 complex with oxalic acid. Take up your crude cholesterol in 5 mL of 1,2-dichloroethane in a 50 mL Erlenmeyer flask. Add 80 mg of oxalic acid, and heat to reflux. Let the flask cool. After twenty minutes (clean up the lab!), swirl the flask in ice water. The contents should gel into a mush of crystals. Vacuum filter with 1,2-dichloroethane, suck dry, and spread out to dry. Take up the white residue in a 50 mL Erlenmeyer flask with 5 mL of water. Heat to reflux, chill in ice water, and vacuum filter. This should give pure white cholesterol, mp = 141-143 oC. Record the melting point and weight. 
Option #2: Take up the crude cholesterol in 5 mL of CH2Cl2 in a 50 mL round bottomflask. Spot a TLC plate in the left lane and the middle lane with the CH2Cl2 solution. Add 0.5 mL of Dess-Martin reagent in CH2Cl2, and warm briefly. Spot the solution in the middle and the right lanes of the same TLC plate, and develop in 1:4 EtOAC/pet ether. If a lot of starting material still remains, warm the solution again, and check it again. When the starting material is almost all converted, save a little of the CH2Cl2 solurion. Rotovap the rest of the solution, add 8 mL of acetone and 20 mg pTsOH, and warm it again to reflux. Spot the TLC plate middle and right, and develop it in 1:4 EtOAC/pet ether. This time, before you visualize the TLC plate with I2, check it with the UV light. You should see a UV spot for cholestenone. TLC Rf’s in 1:9 EtOAC/pet ether: cholesterol = 0.28, 5-cholesten-3-one = 0.60, 4-cholesten-3-one = 0.41. Alternatively, the oxidation can be carried out with the Brown protocol. To purify the 4-cholesten-3-one, add 2 g of flash silica gel to the acetone solution and rotavap it. Build a dry column with 10 grams of flash silica gel. Tap it to settle the silica gel, then add the dry powder with your reaction mixture, and then sand on top. Elute with a mixture of 2 mL of EtOAc and 100 mL of petroleum ether, then with a mixture of 5 mL of EtOAc and 95 mL of petroleum ether. Take 10 mL fractions, and check them by TLC. Evaporate the fractions containing 4-cholesten-3-one in a tared round bottom flask, and record the weight and melting point.



Jumat, 30 November 2012

Nicotine

Introduction to Nicotine

Nicotine is named after the tobacco plant Nicotiana tabacum, which in turn is named after the French ambassador in Portugal, Jean Nicot de Villemain, who sent tobacco and seeds to Paris in 1560, and who promoted their medicinal use. Nicotine was first isolated from the tobacco plant in 1828 by physician Wilhelm Heinrich Posselt and chemist Karl Ludwig Reimann of Germany, who considered it a poison. Its chemical empirical formula was described by Melsens in 1843, its structure was discovered by Adolf Pinner and Richard Wolffenstein in 1893, and it was first synthesized by Amé Pictet and A. Rotschy in 1904.


Structure of Nicotine

The molecular formula for nicotine is C10H14N2.

 
Nicotine is a hygroscopic, oily liquid that is miscible with water in its base form. As a nitrogenous base, nicotine forms salts with acids that are usually solid and water soluble. Nicotine easily penetrates the skin. As shown by the physical data, free base nicotine will burn at a temperature below its boiling point, and its vapors will combust at 308 K (35 °C; 95 °F) in air despite a low vapor pressure. Because of this, most of the nicotine is burned when a cigarette is smoked; however, enough is inhaled to cause pharmacological effects.
 

Biosynthesis

The biosynthetic pathway of nicotine involves a coupling reaction between the two cyclic structures that compose nicotine. Metabolic studies show that the pyridine ring of nicotine is derived from nicotinic acid while the pyrrolidone is derived from N-methyl-Δ1-pyrrollidium cation. Biosynthesis of the two component structures proceeds via two independent syntheses, the NAD pathway for nicotinic acid and the tropane pathway for N-methyl-Δ1-pyrrollidium cation.

The NAD pathway in the genus nicotiana begins with the oxidation of aspartic acid into α-imino succinate by aspartate oxidase (AO). This is followed by a condensation with glyceraldehyde-3-phosphate and a cyclization catalyzed by quinolinate synthase (QS) to give quinolinic acid. Quinolinic acid then reacts with phosphoriboxyl pyrophosphate catalyzed by quinolinic acid phosphoribosyl transferase (QPT) to form nicotinic acid mononucleotide (NaMN). The reaction now proceeds via the NAD salvage cycle to produce nicotinic acid via the conversion of nicotinamide by the enzyme nicotinamidase.

The N-methyl-Δ1-pyrrollidium cation used in the synthesis of nicotine is an intermediate in the synthesis of tropane-derived alkaloids. Biosynthesis begins with decarboxylation of ornithine by ornithine decarboxylase (ODC) to produce putrescine. Putrescine is then converted into N-methyl putrescine via methylation by SAM catalyzed by putrescine N-methyltransferase (PMT). N-methylputrescine then undergoes deamination into 4-methylaminobutanal by the N-methylputrescine oxidase (MPO) enzyme, 4-methylaminobutanal then spontaneously cyclize into N-methyl-Δ1-pyrrollidium cation.

The final step in the synthesis of nicotine is the coupling between N-methyl-Δ1-pyrrollidium cation and nicotinic acid. Although studies conclude some form of coupling between the two component structures, the definite process and mechanism remains undetermined. The current agreed theory involves the conversion of nicotinic acid into 2,5-dihydropyridine through 3,6-dihydronicotinic acid. The 2,5-dihydropyridine intermediate would then react with N-methyl-Δ1-pyrrollidium cation to form enantiomerically pure (–)-nicotine.


Isolation of Nicotine
Nicotine, (S)­-3­-(1­-methyl­-2­-pyrrolidinyl) pyridine, is the most abundant of the volatile alkaloids in the tobacco leaf. The primary commercial source of nicotine is by extraction from the plant Nicotinia tabacum and Nicotinia rustica. Nicotine acts on nicotinic cholinergic receptors, affects most organ systems in the body and is a highly addictive drug. Nicotine normally makes up about 5 percent of a tobacco plant, by weight. Cigarettes contain 8 to 20 milligrams (mg) of nicotine (depending on the brand), but only approximately 1 mg is actually absorbed in the human body.

Procedure:
  1. Weigh 10 g of cigarettes leaves in beaker.
  2. Add 100ml NaOH solution and stir very well for 15 min. 
  3. Filter in Buchner using glass wool and press the cigarettes very well by using other beaker. 
  4. Transfer the cigarettes again to beaker. 
  5. Add 30ml DW and stir and filter again. 
  6. Collect the filtrate together. (If there is any impurities re-filter). 
  7. Transfer the filtrate to the SF and extract by 25ml ether. 
  8. Repeat the extraction 3times. 
  9. Gather the 4 filtrates in conical flask. 
  10. Dry by using 1teaspoon anhydrous potassium carbonate. 
  11. Filter. 
  12. Evaporate ether on water bath.(Avoid extra heat because nicotine is hydrolyzed by extreme heating).
  13. After evaporation of ether add 4ml methanol to dissolve the resulted oil. 
  14. Add 10ml saturated picric acid solution. 
  15. Cool in an ice bath to precipitate the  nicotine di picrate crystals. 
  16. Filter; allow drying and weighing the product.

 

Sabtu, 24 November 2012

Natural Products Chemistry


Mid Semester Exam
Subject                 : Natural Products Chemistry
Credit                    : 2 credits
Lecturer                : Dr. Syamsurizal, M.Si
Day / Date           : Saturday, 24 november 2012
Time                       : 15:30 till 09:00 am  (26 november 2012)

  1. 1.      Put forward your ideas how to convert a compound of natural ingredients that do not have the potential (inactive) can be made into superior compounds that have a high potential for biological activity. Give the example.
    Answer:
                One way to change a compound of natural ingredients that do not have the potential (inactive) can be made into a superior compound that has the potential of high biological activity is the preservation and drying, for example on the plant crown god. God petals contains a variety of chemicals, one of which is a flavonoid. Flavonoids are compounds containing C15 consists of two phenolic nuclei linked to three carbon units. Flavanoid function in the crown of the gods for blood circulation throughout the body and prevent blockages in blood vessels, reduce cholesterol content and reduce penumbunan fat on blood vessel walls, reducing the levels of risk of coronary heart disease, contains anti-inflammatory (anti-inflammatory), serves as an anti-oxidant, helps relieve pain in case of bleeding or swelling.
    Biologically flavonoids play an important role in relation to the pollination of plants by insects. A number of flavonoids have a bitter taste to be able to resist a certain kind of worm. Trees Mahkota Dewa (Phaleria macrocarpa) is known as one of the medicinal plants in Indonesia. Originally from Papua / Irian Jaya. Plant or tree crown of God is often planted as a shade plant. The size is not too big to reach 3 feet tall, has bright red fruit that grows from the main trunk to the branches.
    To extend the shelf life Phaleria, preservation can be done in several ways such as refrigeration, canning, and drying. Drying is done on Phaleria aimed at reducing the moisture content in the material, so that the remaining water can not be used as a medium for microbial life destroyer is in the material, in other words, to extend the shelf life of these Phaleria. Proper drying conditions will menentukn drying high quality results.

  2.  Explain how the idea of a compound of natural ingredients that have a high biological potency and prospective for the benefit of sentient beings can be synthesized in the laboratory.
    Answer:
                A compound of natural ingredients that have a high biological potency and prospectively for the living beings kemaslatan Phaleria used as a cure various kinds of diseases.
    An example is used for the disease:

    Dysentery
    Boil Phaleria skin is dried (15 g) with two cups of water to boil for 15 minutes. Once cool, strain clan drinking water as well. Do it 2-3 times a day.
    Psoriasis
    Cut the fresh Phaleria (three pieces), seeds removed, then sliced ​​thin and dry in the sun to dry. Boil these bulbs with one liter of water over high heat. Once boiling, reduce heat and simmer until the remaining quarter. Once cool, strain and drink the water twice a day, each half. If symptoms of poisoning, lower the dose or discontinue use.
    Eczema, hives
    Wash fresh petals god taste, and grind until smooth. Stick it on the sick, and dressing. Replace 2-3 times a day.
    How to extract flavonoids contained in the crown of God laboratory are:
    • Created solution BAW BAW 4:1:5 and 9:2:6 in the funnel
    • To be taken the next day the solution is at the bottom
    • Prepared 4 chambers each containing BAW 4:1:5, 9:2:6 BAW, n-hexane, and methanol
    • filter paper inserted into each chamber and allowed to stand until saturated
    • Weighed 10 grams of powder Phaleria
    • input into the tool percolator
    • Extracted using solvents n-hexane 250 mL
    • The residue was extracted again using a percolator with a methanol 80% to clear
    • Accommodated n-hexane and non-polar compounds
    • The powder was taken and dried, soaking again by adding methanol as 200ml
    • It was found that the methanol extract of flavonoids contained therein
    • methanol extract was concentrated using a rotary evaporator
    • Obtained extract concentrated and stored in sealed containers
    • concentrated extract spotted on TLC plates 4
    • Each plate is inserted into the chamber containing the BAW 4:1:5, 9:2:6 BAW, n-hexane
    • Detected spots under visible light and UV light 254 nm and 366 nm
    • Noted the color spots and Rf of each developer used
    • Determined the best and eluent used for separation by preparative TLC

  3.  Explain the basic rules in choosing a solvent for the isolation and purification of a compound of natural ingredients. Give the example for 4 classes of compounds of natural products: terpenoids, alkaloids, flavonoids, and steroids.
    Answer:
                In choosing a solvent for the isolation and purification of a compound ingredient is a natural solvent that meets the following requirements:
    a. Dissolves perfect component of a compound of natural ingredients contained in the plant.
    b. Mempunuyai low boiling point.
    c. Does not mix with water.
    d. Inert, does not react with the components of a compound of natural ingredients.
    e. Has a boiling point, when evaporated leaving no residue.
    f. Price is cheap.
    g. Whenever possible, non-flammable.
    h. More volatile

    Isolation of flavonoids from green tea leaves using solvent diethyl ether.
    In the solvent extraction process should choose the appropriate type of flavonoid required so should consider the polarity of the solvent. Types of non-polar flavonoids (eg, isoflavones, flavanones, flavones and flavonols alcohol) was extracted using chloroform, dichloromethane, diethyl ether, or ethyl acetate, while the flavonoid glycoside and aglycone would be more appropriate extracted with alcohol or alcohol-water mixture. To glycosides increased solubility if the water or alcohol-water mixture. Generally most of the extraction process materials containing flavonoids is done simply with the addition of direct solvent extraction.

    Isolation of alkaloid compound that is caffeine from the black waste using chloroform solvent because it can produce high caffeine marinade.

    Isolation of compounds from the leaves of tread liman steroid use ethanol because it can dissolve almost all secondary metabolic compounds. Besides ethanol is also volatile so easily evaporated from the extract.

    Isolation of antibacterial compounds active terpenoids in herb meniran using solvent methanol and n-hexane. Why use methanol, because methanol is a semi-polar solvent that can dissolve many compounds and methanol are also more volatile and easier to come by than other solvents.

     
  4.  Explain the basic starting point for the determination of the structure of an organic compound. When the compounds of natural ingredients such as caffeine tersebuat is. Put forward your ideas matter - whatever the subject matter is required in determining the overall structure.
    Answer:
                for preliminary identification of any isolate flavonoid compounds were performed by observing the color of fluorescence under ultraviolet light before and after the addition of ammonia vapor, followed by ultraviolet spectrophotometer to see the slide batokromik after reacted with specific reagents, the obtained results as shown in Table 1 and Figure 4, 5, 6, 7, 8, and 9. From the results of this analysis can be discussed as follows:
    Chromatogram of ethanol extract fractionation results
    Description:
    1 = fraction of chloroform, ethyl acetate fraction 2 =, 3 = n-butanol Fraction III, 4 = n-Butanol Fraction I, 5 = n-butanol Fraction II, 6 = fraction of water.
    Developer: n-butanol-water-as.asetat (60:22:1,2)
    Apparition spotting: Lar. Aluminum chloride 5%, UV rays and ammonia vapor
    Data shift the wavelength of maximum absorption isolate compounds
    The results of this preliminary investigation on compound leads flavonol glycosides substituted with OH-3 and OH-4 have ', or flavonoids with OH-5, or flavanones with OH-5 or kalkon without OH on ring B. It is based on the dark purple spots under ultraviolet UV, and the color changed to yellow after reacted with ammonia vapor. In methanol solution of this compound gives two maximum absorption bands are bands I and II 258.0 358.0 indicating that the compound was flavones or flavanones. The existence of the shoulder on the maximum absorption bands II showed the presence of 2 or more O atoms in the ring B. With the addition of sodium hydroxide maximum absorption bands I to 413.0, a shift batokromik 55 nm and without a decrease in intensity, suggesting the existence of OH-4 'free. The formation of new bands with maximum absorption 333 indicate the presence of OH-7 free. So the compound leading to flavonol not kalkon.
    UV spectrum of flavonoids SA-DE-1




    UV spectrum of flavonoids SA-DE-2

    With the addition of sodium acetate maximum absorption bands II shifted 15 nm with no decrease in intensity, this further strengthens the presence of free OH-7, with the addition of boric acid to sodium acetate solution I shifted maximum absorption bands at 22 nm, it showed no ring B ortodihidroksi . The addition of aluminum chloride resulted in a shift of maximum absorption bands batokromik I was 53 nm, indicating the existence of OH-5 free without oxygenation at positions 6 and shift decreases on the addition of hydrochloric acid to the tape I showed ortodihidroksi group. From the above data, the structure of the lead compound flavonol OH-3 substituted with OH at position C atom number 5, 7, 4 ', 5', and by looking at the results of the derivatization and infrared spectra of compounds SA-DE-1 leads to the structure of the compound routine. Results derivatization and infrared spectrum can be seen in Figure 10, 11, 12, 13, 14, 15, 16, and 17.
    The results of the preliminary investigation isolates SA-DE-2 with a look at the dark purple spots under UV light and turns yellow with ammonia vapor, and the maximum absorption bands I 348.0 nm and 267.0 nm bands II in methanol, then this compound leads the structure of the flavonol 3-OH substituted or kalkon. With the addition of sodium hydroxide, the maximum absorption bands I batokromik shifted by 53 nm to 401.0 nm with no reduction in intensity,


    UV spectrum of flavonoids SA-DE-3